Question

Растровое изображение 128х128 пикселей занимает 2 Кб памяти. Каково число цветов в палитре?

Answer 1

128*128 = 16384 пикселя = 16384 бит информации.

16384 бит информации/8 бит/байт = 2 кб. => на одну точку приходится 1 бит, то есть в палитре 2 цвета. Каждая точка либо 0 (чёрный), либо 1(белый).

Answer 2

Решение. K =128 х 128 I =2 Кб N – ? i
= 2 х 1024 х 8/(128 х 128) = 2 х 2 10 х
2 3 /(2 7 х 2 7 ) = 2 1+10+3 /2 7+7 = =
2 14 /2 14 = 1 (бит). N = 2 1 = 2.

Answer 3

Calculating the Number of Colors in the Palette

To calculate the number of colors in the palette for a 128x128 pixel image that occupies 2 KB of memory, we can use the formula N = 2^i, where i is the number of bits used to represent each pixel.

Using the provided information, we can calculate the number of colors in the palette:

Step 1: Calculate the total number of pixels in the image: - 128 x 128 = 16,384 pixels

Step 2: Calculate the number of bits used to represent the image: - 2 KB = 2 * 1024 bytes = 2 * 1024 * 8 bits = 16,384 bits - Each pixel requires 1 bit of memory to represent the color.

Step 3: Calculate the number of colors in the palette using the formula N = 2^i: - N = 2^i - i = 1 (since each pixel requires 1 bit to represent the color) - N = 2^1 = 2 colors

Therefore, the number of colors in the palette for the 128x128 pixel image is 2 colors.