Question

Помогите решить, пожалуйста! Дан фрагмент программы. Что в результате выполнения будет на экране? i=1 k=1 while i<4 i=i+(2*i+1) mod (2*i) k=k+k*i wend print k 70 65 64 60

Answer 1

Правильный ответ - 60.

Answer 2

Given Code Fragment

The given code fragment is as follows: ``` i=1 k=1 while i<4 i=i+(2*i+1) mod (2*i) k=k+k*i wend print k ```

Result of Execution

To determine the result of executing the given code fragment, let's analyze it step by step:

1. Initialize the variables `i` and `k` to 1. 2. Enter the `while` loop. 3. In the loop: - Update the value of `i` using the expression `i=i+(2*i+1) mod (2*i)`. - Update the value of `k` using the expression `k=k+k*i`. - Repeat the loop until `i` is no longer less than 4. 4. Exit the `while` loop. 5. Print the value of `k`.

To determine the exact value of `k` that will be printed, we need to simulate the execution of the code.

- Iteration 1: - `i` is initially 1. - `i` is updated to `1 + (2*1+1) mod (2*1) = 1 + 3 mod 2 = 2`. - `k` is updated to `1 + 1*1 = 2`. - Iteration 2: - `i` is now 2. - `i` is updated to `2 + (2*2+1) mod (2*2) = 2 + 5 mod 4 = 3`. - `k` is updated to `2 + 2*2 = 6`. - Iteration 3: - `i` is now 3. - `i` is updated to `3 + (2*3+1) mod (2*3) = 3 + 7 mod 6 = 4`. - `k` is updated to `6 + 6*3 = 24`. - Iteration 4: - `i` is now 4, which is not less than 4, so the loop terminates. - Print Statement: - The value of `k` is 24, so `24` will be printed.

Therefore, the output of executing the given code fragment will be `24`.

Please let me know if you need any further assistance!