Question

A1:=10/(19x)a2:=a1/xa3:=a2/xa4:=a3/xy:=a1+a4 решите плиз

Answer 1

$\displaystyle a_1= \frac{10}{19x}; \quad a_2= \frac{a_1}{x}= \frac{10}{19x^2}; \quad a_3= \frac{a_2}{x}= \frac{10}{19x_3}; \\ \\ a_4= \frac{a_3}{x}= \frac{10}{19x^4}; \quad y=a_1+a_4=\frac{10}{19x}+ \frac{10}{19x^4}= \frac{10}{19x}\left (1+ \frac{1}{x_3}\right)$

Answer 2

Solving the Equations

To solve the given set of equations, let's start by substituting the value of a1 into the subsequent equations.

1. a1 = 10/(19x) 2. a2 = a1/x 3. a3 = a2/x 4. a4 = a3/x

Substitute the value of a1 into a2: - a2 = (10/(19x))/x = 10/(19x^2)

Substitute the value of a2 into a3: - a3 = (10/(19x^2))/x = 10/(19x^3)

Substitute the value of a3 into a4: - a4 = (10/(19x^3))/x = 10/(19x^4)

Now, we have the values of a1, a2, a3, and a4 in terms of x.

Next, let's calculate the value of y: - y = a1 + a4 - y = 10/(19x) + 10/(19x^4)

Final Solution

So, the final solution for the given equations is: - a1 = 10/(19x) - a2 = 10/(19x^2) - a3 = 10/(19x^3) - a4 = 10/(19x^4) - y = 10/(19x) + 10/(19x^4)