Question

Составьте алгоритм и программу вычисления значений функции на произвольном отрезке с произвольным шагом: y = x2 - 1 - при -2 <= x <= 2; y = √(x - 1) - в остальных случаях.

Answer 1

INPUT "a="; a 'Начало отрезка
INPUT "b="; b 'Конец отрезка
INPUT "h="; h 'Шаг
x = a
WHILE x <= b
    PRINT "x="; x, "y=";
    SELECT CASE x
        CASE -2 TO 2
            PRINT x * x - 1
        CASE ELSE
            IF x >= 1 THEN
                PRINT SQR(x - 1)
            ELSE PRINT "Не существует"
            END IF
    END SELECT
    x = x + h
WEND

Answer 2

Algorithm and Program for Calculating Function Values

To calculate the values of the function y = x^2 - 1 on an arbitrary interval with an arbitrary step, and y = √(x - 1) in all other cases, you can use the following algorithm and program:

Algorithm:

1. Define the start and end points of the interval and the step size. 2. Initialize an empty list to store the x and y values. 3. Iterate through the interval with the specified step size. 4. For each x value: - If x is within the range -2 <= x <= 2, calculate y = x^2 - 1. - If x is outside this range, calculate y = √(x - 1). 5. Store the x and y values in the list. 6. Return the list of x and y values.

Program (Python):

```python import math

def calculate_function_values(start, end, step): result = [] x = start while x <= end: if -2 <= x <= 2: y = x**2 - 1 else: y = math.sqrt(x - 1) result.append((x, y)) x += step return result

# Example usage start_point = -3 end_point = 3 step_size = 0.5 values = calculate_function_values(start_point, end_point, step_size) print(values) ```

This program defines a function `calculate_function_values` that takes the start point, end point, and step size as input and returns a list of tuples containing the x and y values. It uses a while loop to iterate through the interval and calculates the corresponding y values based on the given conditions.

Let me know if you need further assistance!