Question

Pascal. Дан массив A[N]. Сформировать массив В из положительных элементов, кратных 3 массива А.

Answer 1

// PascalABC.NET 3.0, сборка 1160 от 05.02.2016
begin
  var a:=ArrRandom(ReadInteger('n='),-50,50); a.Println;
  var b:=a.Where(x->(x>0) and (x mod 3=0)).ToArray.Println
end.

Тестовое решение:
n= 15
15 39 -3 -40 6 -47 -19 -19 17 14 7 31 10 -37 -13
15 39 6

Answer 2

Const
  N = 20;
var
  a, b: array[1..N] of integer;
  i, j: integer;
begin
  writeln('Массив A:');
  for i := 1 to N do
  begin
    a[i] := random(199) - 99;
    write(a[i] : 4);
    if (a[i] > 0) and (a[i] mod 3 = 0) then
    begin
      j := j + 1;
      b[j] := a[i];
    end;
  end;
  writeln;
  writeln('Массив B:');
  for i := 1 to j do
    write(b[i] : 4);
end.

Пример работы программы:
Массив A:
   3  73  -1 -35  97 -14  25  34 -79   5 -39  39  45  96 -85 -59 -14  76 -53 -12
Массив B:
   3  39  45  96

Answer 3

Pascal: Forming Array B from Array A

To form an array B from array A containing positive elements that are multiples of 3, you can use the following Pascal code:

program FormArrayB;
var
  A: array[1..N] of Integer; // Assuming N is the size of array A
  B: array[1..N] of Integer;
  i, j: Integer;
begin
  j := 1;
  for i := 1 to N do
  begin
    if (A[i] > 0) and (A[i] mod 3 = 0) then
    begin
      B[j] := A[i];
      j := j + 1;
    end;
  end;
end.

In this code, we iterate through array A, and for each positive element that is a multiple of 3, we add it to array B. The variable j is used to keep track of the current position in array B.

This code assumes that the size of array A is represented by N. You would need to replace N with the actual size of array A in your specific implementation.

This approach ensures that array B only contains positive elements that are multiples of 3 from array A.

Let me know if you need further assistance with Pascal or any other programming-related queries!