Question

Пропускная способность некоторого канала связи равна 128 000 бит/с. Сколько времени займет передача файла объёмом 500 Кбайт по этому каналу?

Answer 1

128000/1024=125
500/125=4,17 секунд займет передача файла

Answer 2

Calculating File Transfer Time

To calculate the time it will take to transfer a file of 500 Kbytes over a channel with a bandwidth of 128,000 bits per second, we can use the following formula:

Time (in seconds) = File Size (in bits) / Bandwidth (in bits per second)

First, let's convert the file size from Kbytes to bits: 500 Kbytes = 500 * 8 * 1024 bits = 4,096,000 bits

Now, we can use the formula to calculate the time: Time = 4,096,000 bits / 128,000 bits per second = 32 seconds

So, the transfer of a file with a size of 500 Kbytes over a channel with a bandwidth of 128,000 bits per second will take approximately 32 seconds.