Question

Значения элементов двумерного массива А размером 5x5 задаются с помощью вложенного цикла в представленном фрагменте программы: Паскаль Алгоритмический язык for i:=1 tо 5 do for j:=1 tо 5 do begin A[i,j]:= i + j; end; Запишите фрагмент программы, которая позволит найти, сколько элементов массива будут иметь значения больше 5?

Answer 1

Int i,j,count = 0;
for( i = 0; i < 5; i++) {
   for( j = 0; j < 5; j++) {
       A[i][j] = i + j;
       if( A[i][j] > 5 )
       count++;
 }
}

Answer 2

Finding Elements Greater Than 5 in a 5x5 Array

To find the number of elements in the 5x5 array that have values greater than 5, you can use a nested loop to iterate through each element of the array and count the elements that meet the condition.

Here's a code fragment that accomplishes this in Pascal:

program CountElementsGreaterThan5;
var
  A: array[1..5, 1..5] of Integer;
  i, j, count: Integer;
begin
  count := 0;
  for i := 1 to 5 do
    for j := 1 to 5 do
    begin
      A[i, j] := i + j;
      if A[i, j] > 5 then
        count := count + 1;
    end;
  writeln('The number of elements in the array with values greater than 5 is: ', count);
end.

In this program fragment, the variable `count` is used to keep track of the number of elements in the array `A` that have values greater than 5. The nested loops iterate through each element of the array, and if the value of the element is greater than 5, the `count` variable is incremented.

This program will output the total number of elements in the array `A` that have values greater than 5.

Feel free to ask if you have any further questions or need additional assistance!