Question

средняя скорость передачи данных по некоторому каналу связи равна 29 Кбит/с. сколько секунд потребуется для передачи по этому каналу 50 страниц текста если посчитать что один символ кодируется одним байтом и на каждой странице в среднем 96 символов?

Answer 1

50стр. по 96 символов, каждый из которого по бо 1 байту, то в общем текст=4800 байт
29 Кбит = 29696 бит = 3712 байт

4800/3712 приблизительно= 1,3 сек

 

 

Answer 2

Calculation of Time Required for Data Transmission

To calculate the time required for data transmission, we need to consider the average data transfer rate and the size of the data to be transmitted.

Given: - Average data transfer rate: 29 Kbit/s - Number of pages of text: 50 - Average number of characters per page: 96

To calculate the time required for data transmission, we can follow these steps:

1. Calculate the total number of characters in the text: - Number of pages * Average number of characters per page = 50 * 96 = 4800 characters

2. Convert the number of characters to bytes: - Since one character is encoded as one byte, the number of bytes will be the same as the number of characters.

3. Calculate the total data size in kilobits: - Number of bytes * 8 (to convert bytes to bits) = 4800 * 8 = 38400 bits

4. Calculate the time required for data transmission: - Total data size / Average data transfer rate = 38400 bits / 29 Kbit/s

Let's calculate the time required:

38400 bits / 29 Kbit/s = 1324.138 seconds

Therefore, it will take approximately 1324.138 seconds to transmit 50 pages of text with an average of 96 characters per page at a data transfer rate of 29 Kbit/s.

Please note that the above calculation assumes ideal conditions and does not account for any overhead or latency in the transmission process.