Question

Даны 7 одномерных массивов a,b,c,d,e,f,g на 15, 13, 8, 11, 14, 10, 9 элементов соответственно. Вывести имена массивов в порядке возрастания их минимальных элементов.Заполнение массивов,поиск минимального элемента оформить в виде подпрограмм.Для решения воспользоваться двумя вспомогательными массивами.

Answer 1

//PascalABC.NET версия 3.2, сборка 1389
//Если программа не запускается, то обновите версию

function CreateArray(length: integer): array of integer;
begin
    var a := new integer[length];
    for var i := 0 to length - 1 do
        a[i] := Random(0, 100);
//    Println(a);
    Result := a;
end;

begin
    var arrays := new List<(char, array of integer)>();
    arrays.Add(('a', CreateArray(15)));
    arrays.Add(('b', CreateArray(13)));
    arrays.Add(('c', CreateArray(08)));
    arrays.Add(('d', CreateArray(11)));
    arrays.Add(('e', CreateArray(14)));
    arrays.Add(('f', CreateArray(10)));
    arrays.Add(('g', CreateArray(09)));
    
    foreach var a in arrays.OrderBy(a -> a.Item2.Min()) do
    begin
        Println(a.Item1, a.Item2.Min());
    end;
end.

Answer 2

Problem Analysis

To solve this problem, we need to create seven one-dimensional arrays and fill them with the given elements. Then, we need to find the minimum element in each array and sort the array names based on the minimum elements in ascending order. We can use two auxiliary arrays to store the minimum elements and the corresponding array names. Finally, we can print the array names in the sorted order.

Solution

Here's the step-by-step solution to the problem:

1. Create seven one-dimensional arrays: `a`, `b`, `c`, `d`, `e`, `f`, and `g`. 2. Fill the arrays with the given elements: `a = [15, ...]`, `b = [13, ...]`, `c = [8, ...]`, `d = [11, ...]`, `e = [14, ...]`, `f = [10, ...]`, and `g = [9, ...]`. 3. Create two auxiliary arrays: `minElements` and `arrayNames`. 4. Iterate over each array and find the minimum element using a helper function `findMinElement`. 5. Store the minimum element in the `minElements` array and the corresponding array name in the `arrayNames` array. 6. Sort the `arrayNames` array based on the values in the `minElements` array in ascending order. 7. Print the array names in the sorted order.

Here's the implementation in Python:

def findMinElement(arr):
    minElement = arr[0]
    for i in range(1, len(arr)):
        if arr[i] < minElement:
            minElement = arr[i]
    return minElement

# Step 1: Create arrays
a = [15, ...]
b = [13, ...]
c = [8, ...]
d = [11, ...]
e = [14, ...]
f = [10, ...]
g = [9, ...]

# Step 2: Create auxiliary arrays
minElements = []
arrayNames = ['a', 'b', 'c', 'd', 'e', 'f', 'g']

# Step 3-5: Find minimum elements and store in auxiliary arrays
for arr in [a, b, c, d, e, f, g]:
    minElement = findMinElement(arr)
    minElements.append(minElement)

# Step 6: Sort array names based on minimum elements
arrayNames = [name for _, name in sorted(zip(minElements, arrayNames))]

# Step 7: Print array names
for name in arrayNames:
    print(name)

This solution uses a helper function `findMinElement` to find the minimum element in each array. The `sorted` function is used to sort the `arrayNames` array based on the values in the `minElements` array.

Please note that the code provided above is a general solution to the problem. You will need to replace the `...` with the actual elements for each array.

Let me know if you need any further assistance!