Question

Пользуясь ограничениями: в каждом операторе - только одно арифметическое действие: сложение, вычитание, умножение, напишите на языке Паскаль наиболее короткие алгоритмы вычисления: а) y = x^10.

Answer 1

Begin
read(x); k:=x;
for i:=1 to 10 do
x:=x*k;
writeln(k);
end.

Answer 2

Shortest Algorithm to Calculate y = x^10 in Pascal

To calculate y = x^10 using Pascal with the limitation of only one arithmetic operation in each operator, you can use the following algorithm:

1. Algorithm: - Initialize a variable `result` to store the result. - Calculate `x2` as the square of `x`. - Calculate `x4` as the square of `x2`. - Calculate `x8` as the square of `x4`. - Calculate `x10` as the product of `x8` and `x2`. - Assign the value of `x10` to `result`.

var
   x, x2, x4, x8, x10, result: real;
begin
   { Input value of x }
   readln(x);
   
   { Calculate x^2 }
   x2 := x * x;
   
   { Calculate x^4 }
   x4 := x2 * x2;
   
   { Calculate x^8 }
   x8 := x4 * x4;
   
   { Calculate x^10 }
   x10 := x8 * x2;
   
   { Assign the value of x^10 to result }
   result := x10;
   
   { Display the result }
   writeln('Result: ', result);
end.

This algorithm uses only multiplication as the arithmetic operation and calculates the value of x^10 by breaking it down into smaller exponentiations to adhere to the given limitation.