Question

Для заданного числа N составьте программу вычисления суммы S=1/2-1/3+1/4-1/5+..+1/n, где n натуральное число.

Answer 1

///PascalABC.NET (версия 3.1, сборка 1198 от 11.03.2016)
var i,n: integer;
    s:real;
begin
  readln(n);
  s:=0;
  for i:=2 to n do  begin
  if i mod 2=0 then s:=s+1/i
     else s:=s-1/i ;
  end;
  writeln(s);
end.

Answer 2

Program to Calculate Sum of a Series

To calculate the sum of the series S = 1/2 - 1/3 + 1/4 - 1/5 + ... + 1/n, where n is a natural number, you can use the following Python program:

def calculate_sum(n):
    result = 0
    sign = 1
    for i in range(2, n+1):
        result += sign * (1/i)
        sign *= -1
    return result

# Example usage
n = 5
sum_result = calculate_sum(n)
print("The sum of the series is:", sum_result)

This program defines a function `calculate_sum` that takes a natural number `n` as input and calculates the sum of the series using a loop. It iterates through the numbers from 2 to `n` and alternates the sign of each term to achieve the alternating addition and subtraction pattern in the series.

You can replace the value of `n` with any natural number to calculate the sum for a specific value of `n`.

Note: This program assumes that the input `n` is a positive integer.