Question

Помогите пожалуйста написать или на рисовать алгоритм проверки числа на четность

Answer 1

Var
i:integer;

begin
writeln('Введите число');
readln(i);
if ((i mod 2)<>0) then
     writeln('Число нечетное')
else
     writeln('Число четное');
end.

Answer 2

Algorithm for Checking Even or Odd Numbers

To check whether a number is even or odd, you can use the following algorithm:

1. Input the Number: Take the input of the number to be checked.

2. Check for Even or Odd: Divide the number by 2 and check the remainder. If the remainder is 0, then the number is even; otherwise, it is odd.

3. Display the Result: Display the result based on the remainder obtained.

Example in C/C++

Here's an example of how you can implement this algorithm in C/C++:

#include 
using namespace std;

int main() {
   int num;
   cout << "Enter a number: ";
   cin >> num;

if((num%2)==0)
      cout << "The number is even." << endl;
   else
      cout << "The number is odd." << endl;

return 0;
}

This code takes an input number and checks whether it's even or odd using the modulo operator (%). If the remainder is 0, it prints "The number is even," otherwise it prints "The number is odd."

This algorithm and code can be used to quickly determine whether a given number is even or odd.