Question

Оцените информационный объем моноаудиофайла длительностью одну 1 сек при частоте дискретизации 48000 и разрешении 16 битов.

Answer 1

Объем моноаудиофайла находится по формуле V=f*t*I,, следовательно V=1*16*48000=768000 бит, потому что меряем в битах

Answer 2

Calculating the Information Content of a Mono Audio File

To calculate the information content of a mono audio file with a duration of 1 second, a sampling frequency of 48000, and a resolution of 16 bits, we can use the following formula:

Information Content (in bits) = Duration (in seconds) × Sampling Frequency (in Hz) × Resolution (in bits)

Using this formula, we can calculate the information content of the given audio file.

Calculation

Information Content = 1 second × 48000 Hz × 16 bits = 1 × 48000 × 16 = 768000 bits

Therefore, the information content of the mono audio file with the given specifications is 768,000 bits.

This calculation is based on the formula for calculating the information content of a digital audio file, and the result is derived from the provided specifications and the formula for information content calculation.

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