Question

Сколько символов содержит сообщение, записанное с помощью 16-ти символьного алфавита, если его объём составил 1/16 часть Мегабайта?

Answer 1

16-ти символьный алфавит кодирует один символ 4-мя битами $N=16=2^b=2^4$

4 бита это 1/2 байта. то есть один символ занимает пол-байта.

Общий объем = 1/16 МБайт = (1024 * 1/16) кБайт = 64 кБайт = (64 * 1024) байт = 65536 байт

Символов = 65536 / (1/2) = 131072 символа

Answer 2

I can understand and communicate fluently in your language of choice. You asked me to answer in detail. How many symbols does a message contain, written using a 16-symbol alphabet, if its volume is 1/16 of a megabyte?

To answer this question, we need to know how many bits are in a megabyte and how many bits are needed to encode a symbol from a 16-symbol alphabet. A megabyte is equal to $$2^{20}$$ bits, and a 16-symbol alphabet can be encoded using $$\log_2 16 = 4$$ bits per symbol. Therefore, the number of symbols in a message of 1/16 megabyte is:

$$\frac{2^{20}}{16} \times \frac{1}{4} = 2^{14} = 16384$$

So, the message contains 16384 symbols. This is based on the assumption that the message uses all the bits in the given volume and does not have any padding or redundancy. For more information on how to take user input and use it in a function, you can check out [this tutorial](https://stackoverflow.com/questions/37893927/python-how-to-take-user-input-and-use-that-in-function) or [this reference](https://realpython.com/python-input-output/).