Question

Pascal Разработать алгоритм и записать программу табулирования функции используя значение аргумента функции

Answer 1

Const x0=1; xk=4; dx=0.3; y0=0.5; yk=1.5; dy=0.2;
var x,y,z: real; i,j:integer;
begin
writeln(' x   y        z');
x:=x0-dx;
for i:=0 to round((xk-x0)/dx) do
 begin
 x:=x+dx;
 y:=y0-dy;
 for j:=0 to round((yk-y0)/dy) do
  begin
  y:=y+dy;
  z:=cos(x*y-1)+2;
  writeln(x:4:1,' ',y:4:1,' ',z:6:4);
  end;
 end;
end.

Результат:
  x    y     z
1.0 0.5 2.8776
1.0 0.7 2.9553
1.0 0.9 2.9950
1.0 1.1 2.9950
1.0 1.3 2.9553
1.0 1.5 2.8776
1.3 0.5 2.9394
...
3.7 1.5 1.8383
4.0 0.5 2.5403
4.0 0.7 1.7728
4.0 0.9 1.1431
4.0 1.1 1.0332
4.0 1.3 1.5097
4.0 1.5 2.2837

Answer 2

// PascalABC.NET 3.3, сборка 1633 от 10.02.2018
// Внимание! Если программа не работает, обновите версию!

begin
  foreach var x in SeqWhile(1.0,i->i+0.3,i->i<=4.0) do begin
    foreach var y in SeqWhile(0.5,i->i+0.25,i->i<=1.5) do
      Writeln('x=',x:3:1,', y=',y:4:2,', z=',Cos(x*y-1)+2:12:9)
    end
end.

Результат
x=1.0, y=0.50, z= 2.877582562
x=1.0, y=0.75, z= 2.968912422
x=1.0, y=1.00, z= 3.000000000
x=1.0, y=1.25, z= 2.968912422
x=1.0, y=1.50, z= 2.877582562
x=1.3, y=0.50, z= 2.939372713
x=1.3, y=0.75, z= 2.999687516
x=1.3, y=1.00, z= 2.955336489
x=1.3, y=1.25, z= 2.810963120
x=1.3, y=1.50, z= 2.581683089
x=1.6, y=0.50, z= 2.980066578
x=1.6, y=0.75, z= 2.980066578
x=1.6, y=1.00, z= 2.825335615
x=1.6, y=1.25, z= 2.540302306
x=1.6, y=1.50, z= 2.169967143
x=1.9, y=0.50, z= 2.998750260
x=1.9, y=0.75, z= 2.911038733
x=1.9, y=1.00, z= 2.621609968
x=1.9, y=1.25, z= 2.194547708
x=1.9, y=1.50, z= 1.724409753
x=2.2, y=0.50, z= 2.995004165
x=2.2, y=0.75, z= 2.796083799
x=2.2, y=1.00, z= 2.362357754
x=2.2, y=1.25, z= 1.821753944
x=2.2, y=1.50, z= 1.333723979
x=2.5, y=0.50, z= 2.968912422
x=2.5, y=0.75, z= 2.640996858
x=2.5, y=1.00, z= 2.070737202
x=2.5, y=1.25, z= 1.473733665
x=2.5, y=1.50, z= 1.075697621
x=2.8, y=0.50, z= 2.921060994
x=2.8, y=0.75, z= 2.453596121
x=2.8, y=1.00, z= 1.772797905
x=2.8, y=1.25, z= 1.198856384
x=2.8, y=1.50, z= 1.001705224
x=3.1, y=0.50, z= 2.852524522
x=3.1, y=0.75, z= 2.243328794
x=3.1, y=1.00, z= 1.495153895
x=3.1, y=1.25, z= 1.035325854
x=3.1, y=1.50, z= 1.126479102
x=3.4, y=0.50, z= 2.764842187
x=3.4, y=0.75, z= 2.020794828
x=3.4, y=1.00, z= 1.262606284
x=3.4, y=1.25, z= 1.005870324
x=3.4, y=1.50, z= 1.425176053
x=3.7, y=0.50, z= 2.659983146
x=3.7, y=0.75, z= 1.797212557
x=3.7, y=1.00, z= 1.095927858
x=3.7, y=1.25, z= 1.114583665
x=3.7, y=1.50, z= 1.838323784
x=4.0, y=0.50, z= 2.540302306
x=4.0, y=0.75, z= 1.583853163
x=4.0, y=1.00, z= 1.010007503
x=4.0, y=1.25, z= 1.346356379
x=4.0, y=1.50, z= 2.283662185