Question

Найти сумму квадратов первых n натуральных чисел. паскааль

Answer 1

Var
  sum,n:longint;
begin
  writeln('n=? ');
  readln(n);
  sum:=0;
  // основной цикл
  for var i:=1 to n do
    sum:=sum+i*i;
  writeln('При n=',n,' сумма квадратов первых n чисел = ',sum);
end.

Answer 2

Finding the Sum of Squares of the First n Natural Numbers

To find the sum of the squares of the first n natural numbers, you can use the formula:

Sum = n * (n + 1) * (2n + 1) / 6.

Here's how it works:

1. Multiply n by (n + 1) to get the product of the first n natural numbers and the next consecutive number. 2. Multiply the result by (2n + 1) to get the product of the previous result and the next odd number. 3. Finally, divide the result by 6 to get the sum of the squares of the first n natural numbers.

Let's take an example to illustrate this formula. Suppose we want to find the sum of the squares of the first 5 natural numbers:

n = 5

Sum = 5 * (5 + 1) * (2 * 5 + 1) / 6

Sum = 5 * 6 * 11 / 6

Sum = 55

So, the sum of the squares of the first 5 natural numbers is 55.

Please let me know if you have any further questions or if there's anything else I can help you with!