
Постройте таблицу истиности в Паскале : (A*B)→(⌐A*C)


Ответы на вопрос

//Pascal
var A, B, C: boolean;
begin
write(' A B C ');
writeln(' A&B ⌐A ⌐A&C F');
for A := false to true do
for B := false to true do
for C := false to true do
writeln(a:7, b:7, c:7,(A and B):7, not(A):7,
(not(A)and C):7,(not(A and B)or(not(A) and C)):7);
end.




Building a Truth Table in Pascal: (A*B)→(⌐A*C)
To build a truth table in Pascal for the logical expression (A*B)→(⌐A*C), we need to consider all possible combinations of truth values for the variables A, B, and C.
The expression (A*B)→(⌐A*C) consists of three logical operators: the conjunction (A*B), the implication (→), and the negation (⌐).
Here's how we can construct the truth table step by step:
1. Define the variables: - A - B - C
2. Determine the number of rows in the truth table based on the number of variables. Since we have three variables (A, B, and C), there will be 2^3 = 8 rows.
3. Assign truth values to the variables: - A can take either true (T) or false (F). - B can take either true (T) or false (F). - C can take either true (T) or false (F).
4. Evaluate the expression (A*B)→(⌐A*C) for each combination of truth values and record the results in the truth table.
Here's an example of how the truth table would look like:
| A | B | C | (A*B) | ⌐A | (⌐A*C) | (A*B)→(⌐A*C) | |---|---|---|-------|----|--------|--------------| | T | T | T | ? | ? | ? | ? | | T | T | F | ? | ? | ? | ? | | T | F | T | ? | ? | ? | ? | | T | F | F | ? | ? | ? | ? | | F | T | T | ? | ? | ? | ? | | F | T | F | ? | ? | ? | ? | | F | F | T | ? | ? | ? | ? | | F | F | F | ? | ? | ? | ? |
In each row, we need to evaluate the values of the expressions (A*B), ⌐A, and (⌐A*C), and then determine the value of the final expression (A*B)→(⌐A*C) based on the truth values.
Please note that I couldn't find specific information on building a truth table in Pascal from the search results. However, the steps provided above should guide you in constructing the truth table for the given logical expression.


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