Question

Срочно... Дан массив s из n чисел, значения элементов которых находится на интервале от 0 до 400. Заменить все четные элементы стоящие на нечетных местах на противоположные.

Answer 1

Const n=10;
var s:array[1..n] of integer;
i:integer;
begin
Randomize;
writeln('Массив A:');
for i:=1 to n do
 begin
 s[i]:=random(401);
 write(s[i]:5);
 end;
writeln;
p:=1;
for i:=1 to n do
 if (s[i] mod 2=0)and(i mod 2<>0)
  then s[i]:=-s[i];
writeln('Измененный массив:');
for i:=1 to n do write(s[i]:5);
writeln;
end.

Пример:
Массив A:
 75 55 240 33 312 98 126 88 161 123
Измененный массив:
 75 55 -240 33 -312 98 -126 88 161 123

Answer 2

Modifying Array Elements Based on Position and Parity

To solve the given problem, we need to perform the following steps: 1. Iterate through the array. 2. Check if the current element is even and its position is odd. 3. If the conditions are met, replace the element with its opposite value.

Here's a Python code snippet to achieve this:

def modify_array(arr):
    for i in range(len(arr)):
        if i % 2 != 0 and arr[i] % 2 == 0:
            arr[i] = -arr[i]
    return arr

In this code: - We iterate through the array using a for loop. - We use the index `i` to check if the position is odd (`i % 2 != 0`) and if the element is even (`arr[i] % 2 == 0`). - If both conditions are met, we replace the element with its opposite value by negating it (`arr[i] = -arr[i]`).

You can use this `modify_array` function to modify the given array `s` as per the requirements.

Let me know if you need further assistance with this!