Question

22. В автобус помещается не более 20 пассажиров. Пустой автобус подъехал к первой остановке, где в него вошёл один человек. На каждой последующей остановке в автобус входило вдвое больше людей, чем на предыдущей. Начиная с третьей остановки, из автобуса начали выходить по 2 человека на каждой остановке. На пятой остановке автобус ожидало вдвое больше людей, чем на четвёртой, но всем не хватило мест. Сколько человек не поместилось в автобус на пятой остановке? В ответе пиши только число

Answer 1

Количество человек в автобусе на остановках:
1: 1
2: 1 + 2 = 3
3: 3 + 4 - 2 = 5
4: 5 + 8 - 2 = 11
5: 11 + 8*2 = 27
27 - 20 = 7

Ответ: 7 человек.

Answer 2

1. 1
2. 1+2 = 3
3. 3+4-2 = 5
4. 5+8-2 = 11
5. 11+16-2 = 25
Не поместилось в автобус: 25-20 = 5

Answer 3

Problem Analysis

We are given the following information: - The bus can accommodate a maximum of 20 passengers. - The bus starts empty and one person boards at the first stop. - At each subsequent stop, the number of people boarding the bus is twice the number of people who boarded at the previous stop. - Starting from the third stop, two people exit the bus at each stop. - At the fifth stop, there are twice as many people waiting as there were at the fourth stop, but there is not enough space for everyone.

We need to determine how many people did not fit on the bus at the fifth stop.

Solution

To solve this problem, we can simulate the process of people boarding and exiting the bus at each stop.

Let's go step by step:

1. At the first stop, one person boards the bus. The total number of people on the bus is now 1.

2. At the second stop, the number of people boarding is twice the number of people at the previous stop (1 * 2 = 2). The total number of people on the bus is now 1 + 2 = 3.

3. At the third stop, two people exit the bus. The total number of people on the bus is now 3 - 2 = 1. The number of people boarding is twice the number of people at the previous stop (1 * 2 = 2). The total number of people on the bus is now 1 + 2 = 3.

4. At the fourth stop, two people exit the bus. The total number of people on the bus is now 3 - 2 = 1. The number of people boarding is twice the number of people at the previous stop (1 * 2 = 2). The total number of people on the bus is now 1 + 2 = 3.

5. At the fifth stop, there are twice as many people waiting as there were at the fourth stop. Let's assume there were x people at the fourth stop. So, at the fifth stop, there are 2 * x people waiting. However, there is not enough space on the bus for everyone. Since the bus can only accommodate a maximum of 20 passengers, the number of people who did not fit on the bus at the fifth stop is 2 * x - (20 - 3) = 2 * x - 17.

To find the value of x, we can work backward from the fifth stop to the fourth stop. At the fourth stop, the number of people on the bus is 3. So, the number of people who boarded at the fourth stop is (3 - 2) / 2 = 0.5. Since we can't have half a person, we can conclude that x = 0.

Therefore, the number of people who did not fit on the bus at the fifth stop is 2 * 0 - 17 = -17.

Answer

Based on the analysis above, there were no people who did not fit on the bus at the fifth stop.