Question

даны 10 произвольных действительных числа(вводятся с клавиатуры).Подсчитать количество отрицательных чисел помогите составить программу

Answer 1

var a,s,i:integer;
begin
s:=0;
for i:=1 to 10 do
 begin
 write('Число: '); readln(a);
 if a<0 then s:=s+1;
 end;
writeln('Кол-во отрицательных чисел: ',s);
end.

Answer 2

Program Zorkini;
uses crt;
const n=10;
var
  Z: real;
  i,k: integer;
begin
  k:=0;
  for i:=1 to n do
  begin  
    write('Введите ',i,'-e число ');
    readln(z);
    if z<0 then k:=k+1;
  end;
  writeln('Количество отрицательных чисел ',k);
end.

Answer 3

Program to Count Negative Numbers

To create a program that counts the number of negative numbers out of 10 arbitrary real numbers entered from the keyboard, you can use the following Python code:

# Initialize a counter for negative numbers
negative_count = 0

# Input 10 arbitrary real numbers from the keyboard
for _ in range(10):
    num = float(input("Enter a number: "))
    if num < 0:
        negative_count += 1

# Print the count of negative numbers
print("The number of negative numbers entered is:", negative_count)

This program initializes a counter for negative numbers, then prompts the user to input 10 arbitrary real numbers. For each input, it checks if the number is negative and increments the counter accordingly. Finally, it prints the count of negative numbers entered.

This program uses a simple loop and conditional check to achieve the desired functionality.

I hope this helps! If you have any further questions or need additional assistance, feel free to ask.