Question

2. Ниже приведён алгоритм, чему будет равно s после выполнений данного алгоритма? Var a: array[1..10] of integer; i: integer; s: real; Begin s:=0; For i:=1 to 10 do s:=s+i; writeln(s); End. Ответ:

Answer 1

Ответ: 55................

Answer 2

Ответ:

55

Сумма первых 10-ти чисел:

1+2+3+4+5+6+7+8+9+10 = 55

Answer 3

Algorithm Explanation

The given algorithm calculates the value of variable `s` after executing the provided code. Here is a step-by-step breakdown of the algorithm:

1. Declare a variable `a` as an array of 10 integers. 2. Declare variables `i` as an integer and `s` as a real number. 3. Initialize `s` to 0. 4. Start a loop from `i = 1` to `i = 10`. 5. In each iteration of the loop, add the value of `i` to `s`. 6. After the loop ends, print the value of `s`.

Algorithm Execution

Let's execute the algorithm step by step:

1. Declare a variable `a` as an array of 10 integers. 2. Declare variables `i` as an integer and `s` as a real number. 3. Initialize `s` to 0. (No source citation needed) 4. Start a loop from `i = 1` to `i = 10`. 5. In each iteration of the loop, add the value of `i` to `s`. (No source citation needed) - In the first iteration, `i = 1`, so `s` becomes `s + 1 = 0 + 1 = 1`. - In the second iteration, `i = 2`, so `s` becomes `s + 2 = 1 + 2 = 3`. - In the third iteration, `i = 3`, so `s` becomes `s + 3 = 3 + 3 = 6`. - This process continues until the tenth iteration. 6. After the loop ends, print the value of `s`. (No source citation needed)

Result of the Algorithm

Based on the algorithm, the value of `s` after executing the code will be the sum of the numbers from 1 to 10. Let's calculate it:

s = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10
s = 55

Therefore, the value of `s` after executing the algorithm will be 55.

Please note that the provided sources do not directly provide the answer to this specific algorithm. However, the calculation is a simple sum of numbers from 1 to 10, which is a well-known mathematical concept.