Question

Из языка с++ в си (50 баллов) #include int main() { unsigned int x = 4; x = x << 1; std::cout << x; return 0; }

Answer 1

#include <stdio.h>

int main() {

unsigned int x = 4;

x = x << 1;

printf("%i", x);

return 0;

}

Answer 2

Code Explanation

The provided code is written in C++ and performs some operations on an unsigned integer variable `x`. Let's break down the code step by step:

#include

int main() {
    unsigned int x += 4;
    x += x << 1;
    std::cout << x;
    return 0;
}

1. The code includes the `` library, which is needed for input/output operations. 2. The `main()` function is the entry point of the program. 3. An unsigned integer variable `x` is declared and initialized with the value 4. 4. The line `x += x << 1;` performs a bitwise left shift operation on `x` by 1 bit and then adds the result to `x` itself. This is equivalent to multiplying `x` by 2. 5. The line `std::cout << x;` outputs the value of `x` to the console. 6. Finally, the `return 0;` statement indicates that the program has executed successfully.

Output

The code will output the value of `x` after performing the operations. To determine the exact output, we need to evaluate the code:

1. `x += 4;` sets `x` to 4 + 4 = 8. 2. `x += x << 1;` performs a bitwise left shift on `x` by 1 bit, resulting in 16. Then, it adds 16 to `x`, resulting in 8 + 16 = 24. 3. `std::cout << x;` outputs the value of `x`, which is 24.

Therefore, the output of the code will be 24.

Please let me know if you have any further questions!