Question

Дан целочисленный массив A. Найти в нем два наименьших элемента. ПАСКАЛЬ!!!!

Answer 1

Const
n=10;
var
a:array[1..n]of integer;
i,min,j,min2:integer;
begin
   for i:=1 to n do
       begin
            a[i]:=random(100);
             write(a[i]:4);
       end;
min:=a[1];j:=1;min2:=a[1];
for i:=1 to n do
    if a[i]<min then
          begin
              min:=a[i];
              j:=i;
         end;
for i:=1 to n do
    if (a[i]>=min)and(i<>j)and(a[i]<min2)then
      min2:=a[i];
writeln;
writeln(min,' ',min2);
end.

Answer 2

Const
  n=15;
var
  a:array[1..n] of integer;
  i,t,min1,min2:integer;
begin
  Write('Исходный массив: ');
  min1:=1000; min2:=min1;
  for i:=1 to n do
  begin
    t:=Random(50); a[i]:=t;
    if min1>t then
    begin min2:=min1; min1:=t end
    else if min2>t then min2:=t;
    Write(t:3)
  end;
  Writeln(#13#10,'Найденные минимумы: ',min1:3,min2:3);
end.

Тестовое решение:
Исходный массив:  34  8 44 37 37  2 40 46  8 35 44 32  5 14 40
Найденные минимумы:   2  5

Answer 3

Finding the Two Smallest Elements in an Integer Array in Pascal

To find the two smallest elements in a given integer array in Pascal, you can use a simple algorithm that iterates through the array and keeps track of the two smallest elements encountered so far. Here's a basic outline of the algorithm:

1. Initialize two variables, `min1` and `min2`, to the maximum possible integer value. 2. Iterate through the array, and for each element: - If the current element is less than `min1`, update both `min2` to `min1` and `min1` to the current element. - If the current element is greater than or equal to `min1` but less than `min2`, update `min2` to the current element.

Here's a sample Pascal code implementing this algorithm:

program FindTwoSmallest;

var
  A: array of Integer;
  i, min1, min2: Integer;

begin
  // Initialize the array A with the given integers
  // ...

// Initialize min1 and min2 to the maximum possible integer value
  min1 := MaxInt;
  min2 := MaxInt;

// Iterate through the array to find the two smallest elements
  for i := 0 to Length(A) - 1 do
  begin
    if A[i] < min1 then
    begin
      min2 := min1;
      min1 := A[i];
    end
    else if (A[i] < min2) and (A[i] <> min1) then
    begin
      min2 := A[i];
    end;
  end;

// Display the two smallest elements
  writeln('The two smallest elements are: ', min1, ' and ', min2);
end.

This code initializes an array `A` with the given integers and then iterates through the array to find the two smallest elements using the algorithm described above.

Note: The actual implementation of initializing the array `A` with the given integers is not provided in the code snippet above. You would need to populate the array `A` with the actual integer values before running the program.

- The algorithm for finding the two smallest elements in an array is a common approach and is widely used in programming.