Question

помогите выполнить арифметические действия в двоичной системе счисления и произвести проверку 1) 73+44 2) 91-28 3) 27*5 4) 70:7только ответ пожалуйста распишите.

Answer 1

1) 73=1001001 (2)         2)91=1011011 (2)
     44=101100 (2)               28=11100 (2)

+1001001                            -1011011
     101100                                  11100
---------------                              -----------
  1110101= 117 (10)             111111=63 (10)

 

3)27=11011 (2)

    5=101 (2)
    *11011

          101

    ----------

  +  11011

    00000

  11011

 -------------

10000111=135

 

4)70=1000110 (2)

    7=111 (2)

 - 1000110 | 111

     111         |-------
 -------------   1010= 10 (10)

         -111

          111

           ----

               0

Answer 2

Arithmetic Operations in Binary System

Performing arithmetic operations in the binary system involves using the base-2 numbering system, where each digit can only be either 0 or 1. To add, subtract, multiply, or divide binary numbers, we follow similar principles as in the decimal system.

Let's solve the given arithmetic expressions step by step:

1) Addition: 73 + 44

To add binary numbers, we start from the rightmost digits and move towards the left, carrying over any excess when the sum exceeds 1.

   1 0 0 1 0 0 1   (73)
 +   1 0 1 1 0 0   (44)
 _______________
   1 1 1 0 0 1 0   (117 in binary)

Therefore, the sum of 73 and 44 in binary is 1110010.

2) Subtraction: 91 - 28

To subtract binary numbers, we use the concept of borrowing, similar to the decimal system.

   1 0 1 1 0 1   (91)
 -         1 1 0 0   (28)
 __________________
   1 0 0 1 1 0 1   (63 in binary)

Therefore, the difference between 91 and 28 in binary is 1001101.

3) Multiplication: 27 * 5

To multiply binary numbers, we use the same principles as in the decimal system, performing multiplication digit by digit and shifting the partial products.

   1 1 0 1 1   (27)
 ×         1 0 1   (5)
 ______________
   1 1 0 1 1 0 0   (135 in binary)

Therefore, the product of 27 and 5 in binary is 1101100.

4) Division: 70 ÷ 7

To divide binary numbers, we use the same principles as in the decimal system, performing division digit by digit and keeping track of the remainder.

   1 0 0 0 1 0   (70)
 ÷         0 1 1 1   (7)
 __________________
   1 0 0 1   (9 in binary)

Therefore, the quotient of 70 divided by 7 in binary is 1001.

I hope this helps! Let me know if you have any further questions.