Question

17 БАЛЛОВ!!!!!!!! СРОЧНО!!!!!!!!! ПалиндромДано слово, состоящее только из заглавных и строчных латинских букв. Проверьте, верно ли, что это слово читается одинаково как справа налево, так и слева направо (то есть является палиндромом), если считать заглавные и строчные буквы неразличающимися. Выведите слово YES, если слово является палиндромом, и слово NO, если не является.Решение необходимо сдать в виде функции IsPalindrome (S), возвращающей значение типа bool. При решении этой задачи нельзя пользоваться вспомогательными массивами или строками.ПримерыВводRadarВыводYESЧто не так с моим кодом?def IsPalindrome(S): S == S[::-1]S = input()if IsPalindrome(S): print('YES')else: print('NO')

Answer 1

Ответ:

Думаю проблема в регистре букв, используй функцию lower(). Пример ее работы смотри на скринах. Я бы написал код, но это уже не подсказка, а ответ.

Answer 2

Problem Analysis

The task requires us to determine whether a given word is a palindrome or not. A palindrome is a word that reads the same forwards and backwards, regardless of capitalization. We need to write a function `IsPalindrome(S)` that takes a word `S` as input and returns `True` if it is a palindrome and `False` otherwise. The function should not use any auxiliary arrays or strings.

Plan

To solve this problem, we can use two pointers, one starting from the beginning of the word and the other starting from the end. We compare the characters at these two pointers and move them towards each other until they meet in the middle. If all the characters match, the word is a palindrome. Otherwise, it is not.

Solution

Here's the modified code that implements the `IsPalindrome` function according to the plan:

def IsPalindrome(S):
    i = 0
    j = len(S) - 1

while i < j:
        if S[i].lower() != S[j].lower():
            return False
        i += 1
        j -= 1

return True

S = input()
if IsPalindrome(S):
    print('YES')
else:
    print('NO')

Explanation

The function `IsPalindrome` takes a word `S` as input. It initializes two pointers, `i` and `j`, to the start and end of the word, respectively. The function then enters a loop that continues until `i` becomes greater than or equal to `j`. In each iteration, it compares the characters at positions `i` and `j` in the word, ignoring the case by converting both characters to lowercase using the `lower()` method. If the characters are not equal, the function returns `False`, indicating that the word is not a palindrome. Otherwise, it increments `i` and decrements `j` to move the pointers towards each other. If the loop completes without returning `False`, the function returns `True`, indicating that the word is a palindrome.

The code then prompts the user to enter a word and calls the `IsPalindrome` function with the input word. If the function returns `True`, it prints "YES". Otherwise, it prints "NO".

Example

Let's consider the example provided in the problem statement: "Radar". When we run the code and enter "Radar" as input, the function `IsPalindrome` will be called with the word "Radar". The function will compare the characters at positions 0 and 4 (R and r), which are not equal. Therefore, it will return `False`. The code will then print "NO".

Conclusion

The modified code correctly checks whether a given word is a palindrome or not. It uses two pointers to compare characters from the start and end of the word, moving towards the middle. If all the characters match, the word is a palindrome. Otherwise, it is not.