Question

1) a:=-3  a:=-a-a b:=a=2 c:=-b+a*b2) a:=4a:=a*(-a) b:=-a/2c:=(a+b)+3

Answer 1

1) C := 8 + 6 * 8 = 56

2) c := (-16 - 8) + 3 = -21

Answer 2

Let's break down the expressions step by step:

a:=-3 In this line, you are assigning the value -3 to the variable 'a'. So now, 'a' is equal to -3.

a:=-a-a Here, you are assigning the negation of 'a' added to itself to the variable 'a'. This means 'a' will be set to the negation of -3 added to -3, which results in 'a' being 3.

b:=a=2 In this line, you are checking if 'a' is equal to 2 and assigning the result (true or false) to the variable 'b'. Since 'a' is now 3, 'b' will be set to false (0), because 3 is not equal to 2.

c:=-b+a*b Here, you are assigning the value of the negation of 'b' added to 'a' multiplied by 'b' to the variable 'c'. Since 'b' is false (0) and 'a' is 3, 'c' will be set to -0 + (3 * 0), which is 0.

a:=4 Here, you are assigning the value 4 to the variable 'a'. 'a' is now 4.

a:=a*(-a) In this line, you are multiplying 'a' by its negation and assigning the result back to 'a'. So, 'a' will be set to 4 * (-4), which is -16.

b:=-a/2 Here, you are assigning the value of the negation of 'a' divided by 2 to the variable 'b'. Since 'a' is now -16, 'b' will be set to -(-16)/2, which is 8.

c:=(a+b)+3 In this line, you are adding 'a' and 'b' and then adding 3 to the result, which will be assigned to 'c'. 'a' is -16, 'b' is 8, so 'c' will be set to (-16 + 8) + 3, which is -5.

So, after executing these lines of code:

• 'a' will be -16.
• 'b' will be 8.
• 'c' will be -5.