Question

Для записи текста использовался 32-символьный алфавит. Какой объём информации в байтах содержит 11 страниц текста, если на каждой странице расположено 32 строки по 64 символа. ( C дано )

Answer 1

Сначала найдём кол-во (Q) символов в тексте : 32*64= 2048 cимволов.
По формуле Хартли вычислим, сколько памяти занимает 1 символ в памяти : ㏒2(32) = 5 бит. 
Теперь, чтобы получить общее кол-во памяти, которое занимает текст умножим вес 1 символа на кол-во символов : 5* 2048 = 10240 битов
Переводим в байты 10240/8 = 1280 байтов

Answer 2

Calculating Information Volume in Bytes

To calculate the volume of information in bytes contained in 11 pages of text, where each page has 32 rows of 64 characters, we can use the following steps:

1. Calculate the total number of characters in one page. 2. Multiply the total number of characters in one page by the number of pages to get the total number of characters in 11 pages. 3. Convert the total number of characters to bytes.

Let's proceed with the calculations:

1. Total Number of Characters in One Page: - Each page has 32 rows of 64 characters, so the total number of characters in one page is 32 * 64.

2. Total Number of Characters in 11 Pages: - Multiply the total number of characters in one page by the number of pages (11) to get the total number of characters in 11 pages.

3. Conversion to Bytes: - Convert the total number of characters to bytes.

Calculation Steps

1. Total Number of Characters in One Page: - 32 rows * 64 characters = 2048 characters per page.

2. Total Number of Characters in 11 Pages: - 2048 characters per page * 11 pages = 22528 characters.

3. Conversion to Bytes: - Since each character is typically represented by 1 byte, the total volume of information in bytes is 22528 bytes.

Therefore, the 11 pages of text, with each page containing 32 rows of 64 characters, contain a total volume of 22528 bytes of information.