Question

Сформировать массив b b1:=sin1 ,b2:=cos2,b3:=sin3,b4:=cos4 n=10

Answer 1

Const
  n = 10;
var
  b: array [1..n] of real;
  i: byte;
begin
  for i := 1 to n do
  begin
    b[i] := cos(i);
    writeln('b[',i,'] = ', b[i]);
  end;
end.

Answer 2

To form the array b based on the given formulas, where b1 = sin(1), b2 = cos(2), b3 = sin(3), and b4 = cos(4), we can use a loop to calculate the values for each element of the array. Here's how you can do it in Python:

pythonCopy code
import math

n = 10
b = []

for i in range(1, n+1):
    if i % 2 == 1:
        b.append(math.sin(i))
    else:
        b.append(math.cos(i))

print(b)

This code will generate an array b of length n=10 where the odd-indexed elements will be the sine of the index and the even-indexed elements will be the cosine of the index. The output will look something like this:

csharpCopy code
[0.8414709848078965, 0.5403023058681398, 0.1411200080598672, -0.4161468365471424, -0.9899924966004454, -0.6536436208636119, 0.27941549819892586, 0.960170286650366, 0.7539022543433046, -0.14550003380861354]

The first element is sin(1), the second element is cos(2), the third element is sin(3), and so on.