Question

Var k, m: integer; Dat: array(1..10) of integer; Begin Dat (1) i= 12; Dat (2) - 15; Dat (3) := 17; Dat (4) re 15; Dat (5] : 14; Dat (6) := 12; Dat [7] := 10; Dat [8] : 13; Dat (9) * 14; Dat (10) * 15; m := 20; for k:=1 to 10 do if Dat (k) < m then begin m : Dat(k): end; writeln(m): End.

Answer 1

Ответ:

m не меняется, поэтому будет напечатано 20

Answer 2

It seems like you have a Pascal code snippet. Let's go through the code step by step to understand what it does:

1. Declare variables:

   • k and m are integer variables.
   • Dat is an array of integers with 10 elements.

2. Assign values to the array Dat:

   • The code attempts to assign values to the array elements, but there are some syntax errors in the assignments. The correct assignments should be as follows:

pascalCopy code
Dat[1] := 12;
Dat[2] := 15;
Dat[3] := 17;
Dat[4] := 15;
Dat[5] := 14;
Dat[6] := 12;
Dat[7] := 10;
Dat[8] := 13;
Dat[9] := 14;
Dat[10] := 15;

3. Initialize m with the value 20.

4. Loop through the Dat array:

   • The loop goes from k = 1 to 10.
   • For each element in Dat, it checks if the value is less than the value of m.
   • If the condition is true, it assigns the value of Dat(k) to m.

5. Print the value of m.

After correcting the syntax errors, the code should look like this:

pascalCopy code
Var
  k, m: integer;
  Dat: array[1..10] of integer;

Begin
  Dat[1] := 12;
  Dat[2] := 15;
  Dat[3] := 17;
  Dat[4] := 15;
  Dat[5] := 14;
  Dat[6] := 12;
  Dat[7] := 10;
  Dat[8] := 13;
  Dat[9] := 14;
  Dat[10] := 15;

  m := 20;
  for k := 1 to 10 do
  begin
    if Dat[k] < m then
    begin
      m := Dat[k];
    end;
  end;
  
  writeln(m);
End.

With the corrected code, the output will be the smallest value in the Dat array, which is 10.