Question

For x:=5 downto 0 do begin y:=x×x; writeln (y); end ​

Answer 1

Вывод будет равен 10 т. к. у= х*х

Answer 2

The code you provided is written in Pascal programming language. It uses a loop to calculate the square of each number from 5 to 0 and then prints the result.

Here's a step-by-step explanation of the code:

1. The variable x is declared and initialized with the value 5 using the assignment operator :=.

2. The loop begins with the downto keyword, which means the loop will iterate in a decreasing manner from the initial value (5) to the final value (0).

3. The loop body contains the statement y := x * x;. This calculates the square of the current value of x and assigns it to the variable y.

4. The statement writeln(y); is used to print the value of y on the screen.

5. The loop continues to execute with x decreasing by one in each iteration until x becomes 0.

So, when the code runs, it will output the squares of the numbers from 5 down to 0:

25 16 9 4 1 0

Each number is printed on a separate line.