Question

В) var n, s: integer; begin n : = 30; s : = 25; while s < 425 do begin s : = s + 40; n : = n + 10 end; write(n);end.

Answer 1

Ответ: 130

После выполнения n = 130

Answer 2

Ответ:

N=130

Ответ 130

........

Answer 3

The given code snippet is written in Pascal programming language. It initializes two variables, n and s, as integers. The code then enters a while loop with the condition s < 425.

Within the loop, the value of s is increased by 40 (s := s + 40), and the value of n is increased by 10 (n := n + 10). This process continues until the condition s < 425 is no longer satisfied.

Finally, after the loop, the value of n is printed using the write statement.

Let's go through the code step by step to see what the final output will be.

1. Initialization:

   • n is initialized as 30.
   • s is initialized as 25.

2. Loop Execution:

   • Since the initial value of s is less than 425, the loop is entered.
   • The value of s is increased by 40: s := 25 + 40, which becomes 65.
   • The value of n is increased by 10: n := 30 + 10, which becomes 40.

   The loop continues as long as s < 425. On each iteration, s is increased by 40, and n is increased by 10.

   • After the second iteration: s := 65 + 40, which becomes 105. n := 40 + 10, which becomes 50.
   • After the third iteration: s := 105 + 40, which becomes 145. n := 50 + 10, which becomes 60.
   • The process continues until s becomes 425.

3. Loop Termination:

   • After several iterations, s eventually becomes equal to or greater than 425, breaking the loop.

4. Output:

   • The final value of n is 60.
   • The code will print 60 using the write statement.

Therefore, the output of the given code will be 60.