Question

A:= 3+8*4 ; b:=div ( a , 10 ) + 4 ; a:= mod ( b , 10 ) + 12 ; c:= a + b ​

Answer 1

Бэйсик Паскаль
a = 3 + 8*4
b = (a \ 10) + 14
a = (b MOD 10) + 2
c = a + b;
a := 3 + 8*4;
b := (a div 10) + 14;
a := (b mod 10) + 2;
c := a + b;
Си++ Алгоритмический язык
a = 3 + 8*4;
b = (a / 10) + 14;
a = (b % 10) + 2;
c = a + b;
a := 3 + 8*4
b := div(a, 10) + 14
a := mod(b, 10) + 2
c := a + b
Python
a = 3 + 8*4
b = (a // 10) + 14
a = (b % 10) + 2
c = a + b

Answer 2

Let's evaluate the given expressions step by step:

1. A := 3 + 8 * 4 First, we perform the multiplication: 8 * 4 = 32 Then, we add 3 to the result: 3 + 32 = 35 Therefore, A = 35

2. B := div(A, 10) + 4 Here, we divide A by 10 and take the quotient (integer division). div(35, 10) = 3 (as 35 divided by 10 is 3 with no remainder) Then, we add 4 to the quotient: 3 + 4 = 7 Therefore, B = 7

3. A := mod(B, 10) + 12 We take the remainder when B is divided by 10. mod(7, 10) = 7 (as 7 divided by 10 leaves a remainder of 7) Then, we add 12 to the remainder: 7 + 12 = 19 Therefore, A = 19

4. C := A + B We simply add A and B together: 19 + 7 = 26 Therefore, C = 26

So, the final values are: A = 19 B = 7 C = 26