Question

А := 3 b := 5 а := 6+а*b b := b+а/3

Answer 1

а:= 3

b:= 5

а:= 6 + а * b = 6 + 3 * 5 = 6 + 15 = 21

b:= b + а/3 = 5 + 21 / 3 = 5 + 7 = 12

Ответ: 12.

Answer 2

It seems like you are trying to write a series of assignments in a programming-like language. Let's break down what each line does:

1. A := 3: This line assigns the value 3 to the variable A. It's important to note that variable names are case-sensitive, so A and a are different variables.

2. b := 5: This line assigns the value 5 to the variable b.

3. а := 6+а*b: This line assigns the result of the expression 6 + а * b to the variable а. However, there is a problem with this line because а is being used before it's assigned a value. It's better to use A instead of а to avoid confusion between variable names.

4. b := b+а/3: This line adds the value of а divided by 3 to the current value of b and assigns the result back to b. Again, it's better to use A instead of а.

Here's a corrected version of the code with consistent variable names:

plaintextCopy code
A := 3
b := 5
A := 6 + A * b
b := b + A / 3

In this corrected version, we use consistent variable names (capitalized A and lowercase b), and the expressions should be evaluated correctly.