
Вопрос задан 24.06.2023 в 03:58.
Предмет Информатика.
Спрашивает Касіян Андріана.
Summa=0 i=0 while i<=6:summa=summa+i i=i+2 print (summa)


Ответы на вопрос

Отвечает Воронежский Данила.
Ответ:
summa = 0
i = 0
while i <= 6:
summa = summa + i
i=i + 2
print (summa)
Объяснение:



Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.
The code you provided appears to be written in a Python-like programming language. It initializes a variable summa
to 0, and then it enters a while
loop with the condition i <= 6
. Within the loop, it increments the summa
variable by the value of i
and also increments i
by 2 in each iteration. It then prints the value of summa
.
Here's the step-by-step execution of the code:
summa
is initialized to 0.i
is initialized to 0.- The
while
loop begins. Sincei
is initially 0 and the condition isi <= 6
, it evaluates to True, so the loop is entered. - Inside the loop,
summa
is updated tosumma + i
, which is 0 + 0, sosumma
remains 0. i
is updated toi + 2
, which becomes 2.- The value of
summa
(which is still 0) is printed. - The loop continues because
i
(which is now 2) is still less than or equal to 6. - Inside the loop,
summa
is updated tosumma + i
, which is 0 + 2, sosumma
becomes 2. i
is updated toi + 2
, which becomes 4.- The value of
summa
(which is now 2) is printed. - The loop continues because
i
(which is now 4) is still less than or equal to 6. - Inside the loop,
summa
is updated tosumma + i
, which is 2 + 4, sosumma
becomes 6. i
is updated toi + 2
, which becomes 6.- The value of
summa
(which is now 6) is printed. - The loop continues because
i
(which is now 6) is still equal to 6. - Inside the loop,
summa
is updated tosumma + i
, which is 6 + 6, sosumma
becomes 12. i
is updated toi + 2
, which becomes 8.- The value of
summa
(which is now 12) is printed. - The loop exits because
i
(which is now 8) is no longer less than or equal to 6.
So, the code will print the values 0, 2, 6, and 12 in consecutive lines.


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