Question

Помогите с информатикой!! Определите количество принадлежащих отрезку [251763; 514827] натуральных чисел, которые делятся без остатка на сумму своих цифр, и наименьшее из таких чисел. В ответе запишите два целых числа: сначала количество, затем наименьшее число. Нужно написать на паскале

Answer 1

Ответ:

k=0

s=0

mn=514828

for i in range(251763,514827):

   a=str(i)

   for j in range(0,len(a)):

       s=s+int(a[j])

   if i%s==0:

       s=0

       k+=1

       if mn>i:

           mn=i

   else:

       s=0

print(k,mn)

       

Объяснение:

питон

Answer 2

To determine the number of natural numbers belonging to the interval [251763; 514827] that are divisible without remainder by the sum of their digits, and to find the smallest of such numbers, you can write a program in Pascal. Here's an example of how you can approach this problem:

program FindDivisibleNumbers;

var
  num, sum, digit, minNum, count: integer;

begin
  count := 0;
  minNum := 0;

for num := 251763 to 514827 do
  begin
    sum := 0;
    digit := num;

while digit > 0 do
    begin
      sum := sum + digit mod 10;
      digit := digit div 10;
    end;

if (num mod sum = 0) then
    begin
      count := count + 1;

if (minNum = 0) or (num < minNum) then
        minNum := num;
    end;
  end;

writeln(count, ' ', minNum);
end.

In this program, we use a `for` loop to iterate through all the numbers in the given interval. For each number, we calculate the sum of its digits using a `while` loop. If the number is divisible without remainder by the sum of its digits, we increment the `count` variable and update the `minNum` variable if the current number is smaller than the previous smallest number.

After the loop, we output the `count` and `minNum` variables, which represent the number of divisible numbers and the smallest divisible number, respectively.

Please note that this program assumes you have a Pascal compiler installed and configured on your computer. You can copy the code into a Pascal editor or IDE, compile, and run it to get the desired output.

I hope this helps! Let me know if you have any further questions.