Question

ПАСКАЛЬ!!!!Подсчитайте количество элементов одномерного массива, которые совпадают со своим номером и при этом кратны 3.

Answer 1

uses crt;

const n=10;

var a     : array[1..n] of integer;

   i,kol : integer;

begin

 kol:=0;

 randomize;

 for i:=1 to n do begin

   a[i]:=random(10)+1;

 end;

 writeln('Исходный массив');

 for i:=1 to n do begin

   if (a[i]=i) and (a[i] mod 3=0) then kol:=kol+1;

   write(a[i]:3);

 end;

 writeln;

 writeln('Количество элементов ',kol);

end.

Answer 2

Counting Elements in a One-Dimensional Array

To count the number of elements in a one-dimensional array that match their index and are multiples of 3, you can use a simple loop to iterate through the array and check the conditions for each element. Here's a basic example in JavaScript:

function countMatchingElements(arr) {
  let count = 0;
  for (let i = 0; i < arr.length; i++) {
    if (arr[i] === i && arr[i] % 3 === 0) {
      count++;
    }
  }
  return count;
}

// Example usage
let myArray = [0, 3, 6, 3, 8, 5, 12];
let result = countMatchingElements(myArray);
console.log(result); // Output: 3

In this example, the `countMatchingElements` function takes an array as input and iterates through it, checking if each element matches its index and is a multiple of 3. If both conditions are met, the count is incremented.

Note: This example is in JavaScript, but the same logic can be applied in other programming languages.