Question

A = int(input()) b = int(input()) while a!=b: if a>b: else: a=a-b b=b-a print(a) Сколько раз выполнится цикл while при вводе пары чисел 96 и 36?​

Answer 1

Відповідь:

Цикл while виполниться 4 раза

Пояснення:

Answer 2

The provided code is incomplete and contains syntax errors. I'll assume you meant to write the following code:

pythonCopy code
a = int(input())
b = int(input())

while a != b:
    if a > b:
        a = a - b
    else:
        b = b - a

print(a)

Based on the corrected code, let's analyze what happens when the input is 96 and 36.

In the first iteration of the while loop, a is greater than b, so a becomes 60 (a = a - b). The values of a and b are now 60 and 36, respectively.

In the second iteration, a is still greater than b, so a becomes 24 (a = a - b). The values of a and b are now 24 and 36, respectively.

In the third iteration, a is smaller than b, so b becomes 12 (b = b - a). The values of a and b are now 24 and 12, respectively.

In the fourth iteration, a is greater than b, so a becomes 12 (a = a - b). The values of a and b are now 12 and 12, respectively.

Now, in the fifth iteration, a is equal to b, so the condition of the while loop (a != b) is no longer true. The loop terminates.

Therefore, the while loop will execute 4 times for the input pair (96, 36).