Question

Складіть програму з використанням однієї функції зі змінною кількістю аргументів для обчислення сум чисел 1, 3, 5,7, 9 і 6, 8,10. Розробіть програму з рекурсивною функцією обчислення n перших членів геометричної прогресії, перший член якої дорівнює a і знаменник q PYTHON

Answer 1

Ответ:

ниже

Объяснение:

№1

def summ(*numbers):

 return(sum(numbers))

print(summ(1,3,5,7,9))

print(summ(6,8,10))

№2

def geometric_progression(n,q,a):

 progression = [a]

 for k in range(2,n+1):

    progression.append(progression[k-2]*q)

 return(progression)

number = int(input('Введіть кількість перших n-членів: '))

denominator = int(input('Введіть знаменник: '))

first_number = int(input('Введіть перше значення: '))

print(geometric_progression(number,denominator,first_number))

Answer 2

Program to calculate the sum of numbers using a variable number of arguments

To write a program that calculates the sum of numbers using a variable number of arguments, you can define a function that takes in any number of arguments and then iterates over them to calculate the sum.

Here's an example program in Python:

def calculate_sum(*args):
    total = 0
    for num in args:
        total += num
    return total

# Example usage
result = calculate_sum(1, 3, 5, 7, 9, 6, 8, 10)
print("The sum is:", result)

In this program, the `calculate_sum` function is defined with `*args` as the parameter. The `*args` syntax allows the function to accept any number of arguments, which are then stored in a tuple called `args`. The function then iterates over the `args` tuple and adds each number to the `total` variable. Finally, the function returns the total sum.

In the example usage, we pass the numbers 1, 3, 5, 7, 9, 6, 8, and 10 as arguments to the `calculate_sum` function. The result is then printed, which in this case would be 49.

Program to calculate the first n terms of a geometric progression recursively

To write a program that calculates the first n terms of a geometric progression recursively, you can define a recursive function that takes in the first term (a), the common ratio (q), and the number of terms (n) as arguments.

Here's an example program in Python:

def calculate_geometric_progression(a, q, n):
    if n == 1:
        return a
    else:
        return q * calculate_geometric_progression(a, q, n-1)

# Example usage
first_term = 2
common_ratio = 3
num_terms = 5

for i in range(1, num_terms+1):
    term = calculate_geometric_progression(first_term, common_ratio, i)
    print("Term", i, ":", term)

In this program, the `calculate_geometric_progression` function is defined recursively. It checks if the number of terms (n) is equal to 1. If it is, it returns the first term (a). Otherwise, it multiplies the common ratio (q) with the result of recursively calling the function with the first term, common ratio, and n-1 as arguments.

In the example usage, we set the first term to 2, the common ratio to 3, and the number of terms to 5. We then use a loop to calculate and print each term of the geometric progression. The output would be:

Term 1 : 2
Term 2 : 6
Term 3 : 18
Term 4 : 54
Term 5 : 162

Each term is calculated by recursively calling the `calculate_geometric_progression` function with the appropriate arguments.