Question

Тренировочная задача 1 [1 балл] У Тани день рождения. Она взяла из копилки x рублей, купила торт за t рублей, а на оставшиеся деньги решила сводить друзей в кино. Билет стоит b рублей.Скольких друзей Таня может сводить в кино?Сколько денег у неё останется?Задача на пайтоне, должен быть кусок кода

Answer 1

Ответ:

Друзей: (х-t):b

Останется: x - t - ((x-t):b)

Объяснение:

на сколько я поняла задание

Answer 2

Problem Analysis

In this problem, we are given that Tanya has x rubles in her piggy bank. She buys a cake for t rubles and decides to take her friends to the cinema with the remaining money. The ticket costs b rubles. We need to determine how many friends Tanya can take to the cinema and how much money she will have left.

Solution

To solve this problem, we can use the following steps:

1. Read the values of x, t, and b from the user. 2. Calculate the amount of money Tanya will have left after buying the cake by subtracting t from x. 3. Calculate the number of friends Tanya can take to the cinema by dividing the remaining money by the cost of a ticket. 4. Print the number of friends Tanya can take to the cinema and the amount of money she will have left.

Here's the Python code that solves the problem:

x = int(input("Enter the amount of money in Tanya's piggy bank (x): "))
t = int(input("Enter the cost of the cake (t): "))
b = int(input("Enter the cost of a cinema ticket (b): "))

remaining_money = x - t
number_of_friends = remaining_money // b

print("Tanya can take", number_of_friends, "friends to the cinema.")
print("She will have", remaining_money % b, "rubles left.")

Example

Let's say Tanya has 100 rubles in her piggy bank, the cake costs 30 rubles, and a cinema ticket costs 10 rubles. Using the code above, we can calculate that Tanya can take 7 friends to the cinema and she will have 0 rubles left.

Note

Please note that the code assumes the user will enter valid integer values for x, t, and b. If the user enters invalid values (e.g., non-integer values or negative values), the code may produce unexpected results or raise an error. It's always a good practice to include error handling in your code to handle such cases.