Question

В програмі python. Скласти програму яка буде запитувати 2 цілих числа виведе на екран суму, різницю, ділення без остачі, остачу від ділення цих чисел, піднесе число а в степені b, корінь квадратний суми числа а і b

Answer 1

Код на Python:

x = int(input())

y = int(input())

print('Сумма =', x + y)

print('Разность =', x - y)

print('Целочисленное деление =', x // y)

print('Остаток от деления =', x % y)

print('Степень =', x ** y)

print('Корень =', x + y)

Answer 2

To write a program in Python that prompts the user for two integers and displays the sum, difference, division without remainder, remainder of division, the number a raised to the power of b, and the square root of the sum of a and b, you can use the following code:

import math

# Prompt the user for two integers
a = int(input("Enter the first integer: "))
b = int(input("Enter the second integer: "))

# Calculate the sum
sum = a + b

# Calculate the difference
difference = a - b

# Calculate the division without remainder
division = a // b

# Calculate the remainder of division
remainder = a % b

# Calculate a raised to the power of b
power = a ** b

# Calculate the square root of the sum of a and b
square_root = math.sqrt(sum)

# Display the results
print("Sum:", sum)
print("Difference:", difference)
print("Division without remainder:", division)
print("Remainder of division:", remainder)
print("a raised to the power of b:", power)
print("Square root of the sum of a and b:", square_root)

This program uses the `input()` function to prompt the user for two integers. It then performs the necessary calculations using basic arithmetic operators and the `math.sqrt()` function from the math module to calculate the square root. Finally, it displays the results using the `print()` function.

Please note that this program assumes the user will enter valid integer values. If the user enters non-integer values, the program will raise a `ValueError`. You can add error handling to handle such cases if needed.

I hope this helps! Let me know if you have any further questions.