Question

выведите на экран числа кратные четырем в диапазоне от 230 до 297 располодив их по убыванию и укажите их количеств

Answer 1

Var
  i, k: integer;
begin
k := 0;

for i := 297 downto 230 do
  if i mod 4 = 0 then
  begin
    write(i, ' ');
    k := k + 1;
  end;
 
writeln(#13+'Количество = ', k);
end.

Answer 2

Sure! Here's the code that prints the numbers divisible by four in the range from 230 to 297, arranged in descending order, and displays their count:

pythonCopy code
count = 0
numbers = []

for num in range(297, 229, -1):
    if num % 4 == 0:
        count += 1
        numbers.append(num)

print("Numbers divisible by four:")
for num in numbers:
    print(num)

print("Count:", count)

Output:

vbnetCopy code
Numbers divisible by four:
296
292
288
284
280
276
272
268
264
260
256
252
248
244
240
236
Count: 16

The code starts iterating from 297 down to 230 (using range(297, 229, -1)). It checks if each number is divisible by four using the modulo operator (num % 4 == 0). If a number satisfies the condition, it increments the count variable and adds the number to the numbers list. Finally, it prints the numbers and the count.