Question

Составь электронные формулы ионов Be2+ P3- F- K+ помогите пж.

Answer 1

Electron Configurations of Ions

Here are the electron configurations of the ions you mentioned:

- Be2+: Beryllium loses two electrons to form the Be2+ ion. The electron configuration of beryllium is 1s^2 2s^2. When it loses two electrons, the configuration becomes 1s^2 2s^0, which can be simplified as [He]. - P3-: Phosphorus gains three electrons to form the P3- ion. The electron configuration of phosphorus is 1s^2 2s^2 2p^6 3s^2 3p^3. When it gains three electrons, the configuration becomes 1s^2 2s^2 2p^6 3s^2 3p^6, which can be simplified as [Ne]. - F-: Fluorine gains one electron to form the F- ion. The electron configuration of fluorine is 1s^2 2s^2 2p^5. When it gains one electron, the configuration becomes 1s^2 2s^2 2p^6, which can be simplified as [Ne]. - K+: Potassium loses one electron to form the K+ ion. The electron configuration of potassium is 1s^2 2s^2 2p^6 3s^2 3p^6 4s^1. When it loses one electron, the configuration becomes 1s^2 2s^2 2p^6 3s^2 3p^6, which can be simplified as [Ar].

Please note that the simplified configurations are written using the noble gas notation, where the symbol of the noble gas that precedes the ion's electron configuration is enclosed in brackets.

I hope this helps! Let me know if you have any further questions.