Вопрос задан 20.01.2020 в 05:42. Предмет Химия. Спрашивает Бохан Богдан.

В следующих уравнениях расставьте коэффициенты методом электронного баланса , укажите окислитель и

восстановитель: AL+O2=AlO3 MnCO3+KClO3=MnO2+KCl+CO2
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Отвечает Вавилов Захар.
Al(0) + O2(0) --> Al2(+3)O3(-2) Al(0) -3 е -> Al(+3) | 3 | | 4 восстановитель | | 12 | О2(0) +4 е -> 2О(-2) | 4 | | 3 окислитель 4Al + 3O2 --> 2Al2O3 Mn(+2)C(+4)O3(-2) + K(+1)Cl(+5)O3(-2) --> Mn(+4)O2(-2) + K(+1)Cl(-1) + C(+4)O2(-2) Mn(+2) - 2 e -> Mn(+4) | 2 | | 3 восстановитель | | 6 | Cl(+5) + 6 e -> Cl(-1) | 6 | | 1 окислитель 3MnCO3 + KClO3 --> 3MnO2 + KCl + 3CO2
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Balancing the equation AL + O2 = AlO3

To balance the equation AL + O2 = AlO3 using the method of electronic balancing, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

Let's start by balancing the aluminum (Al) atoms. There is one Al atom on the left side and one Al atom on the right side, so the Al atoms are already balanced.

Next, let's balance the oxygen (O) atoms. There are two O atoms on the left side (from O2) and three O atoms on the right side (from AlO3). To balance the O atoms, we need to multiply O2 by 3/2 and AlO3 by 2/3.

The balanced equation is:

2Al + 3/2O2 = AlO3

In this equation, aluminum (Al) is being oxidized from an oxidation state of 0 to +3, while oxygen (O) is being reduced from an oxidation state of 0 to -2. Therefore, aluminum is the reducing agent (or the reductant) and oxygen is the oxidizing agent (or the oxidant).

Balancing the equation MnCO3 + KClO3 = MnO2 + KCl + CO2

To balance the equation MnCO3 + KClO3 = MnO2 + KCl + CO2 using the method of electronic balancing, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

Let's start by balancing the manganese (Mn) atoms. There is one Mn atom on the left side and one Mn atom on the right side, so the Mn atoms are already balanced.

Next, let's balance the carbon (C) atoms. There is one C atom on the left side (from MnCO3) and one C atom on the right side (from CO2). The C atoms are already balanced.

Now, let's balance the oxygen (O) atoms. There three O atoms on the left side (from KClO3) and two O atoms on the right side (from MnO2 and CO2). To balance the O atoms, we need to multiply KClO3 by 2/3.

The balanced equation is:

MnCO3 + 2/3KClO3 = MnO2 + KCl + CO2

In this equation, manganese (Mn) is being reduced from an oxidation state of +4 to +2, while chlorine (Cl) is being oxidized from an oxidation state of -1 to 0. Therefore, manganese is the oxidizing agent (or the oxidant) and chlorine is the reducing agent (or the reductant).

Please note that the coefficients provided above are approximate and may need to be simplified further.

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