Question

вычислить массу соли, если в реакцию вступило 2 моль серной кислоты и избыток цинка

Answer 1

Zn+H2SO4=ZnSO4+H2

n(H2SO4)=2 моль ;берем моль для соли серной кислоты,потому что цинк находится в избытке

n(ZnSO4)=2 моль

m(ZnSO4)=2 моль*161 г/моль=322 г 

Answer 2

Calculating the Mass of Salt in the Reaction

To calculate the mass of salt produced when 2 moles of sulfuric acid react with an excess of zinc, we can use the chemical equation for the reaction and the molar masses of the substances involved.

The balanced chemical equation for the reaction between sulfuric acid (H2SO4) and zinc (Zn) is as follows: H2SO4 + Zn → ZnSO4 + H2

From the balanced chemical equation, we can see that 1 mole of sulfuric acid (H2SO4) reacts with 1 mole of zinc (Zn) to produce 1 mole of zinc sulfate (ZnSO4) and 1 mole of hydrogen gas (H2).

Given that 2 moles of sulfuric acid are reacting, we can determine the amount of salt produced and then calculate its mass.

Calculating the Amount of Salt Produced

The molar mass of zinc sulfate (ZnSO4) is 161.47 g/mol. Using the stoichiometry of the reaction, we can calculate the amount of zinc sulfate produced: 1 mole of sulfuric acid (H2SO4) produces 1 mole of zinc sulfate (ZnSO4).

Therefore, 2 moles of sulfuric acid will produce 2 moles of zinc sulfate.

Calculating the Mass of Salt Produced

Now, we can calculate the mass of zinc sulfate produced: Molar mass of zinc sulfate (ZnSO4) = 161.47 g/mol.

Mass of zinc sulfate produced = Number of moles of zinc sulfate produced × Molar mass of zinc sulfate Mass of zinc sulfate produced = 2 moles × 161.47 g/mol Mass of zinc sulfate produced = 322.94 g

So, the mass of zinc sulfate produced when 2 moles of sulfuric acid react with an excess of zinc is 322.94 grams.