Question

Чему равна молярная концентрация раствора,содержащего 4,0г гидроксида натрия в 2л раствора?

Answer 1

Дано:
m(NaOH) = 4 r
V(p-pa NaOH) = 2 л
Найти:
См-?
M(NaOH) = 40 г/моль
n(NaOH)=m(NaOH)/M(NaOH) = 4 г/40 г/моль = 0,1 моль
См=n(NaOH)/V(p-paNaOH) = 0,1 моль/2 л = 0,05 моль/л
Ответ: 0,05 моль/л

Answer 2

Дано:
m(NaOH)=4 г
V(раствора)=2 л
Найти:
C(раствора)=?

Решение:
C=n/V
n(NaOH)=4/40=0.1(моль)
С(раствора)=0.1/2=0.05(моль/л).
Ответ: молярная концентрация раствора 0.05 моль/л.

Answer 3

Molar Concentration of Sodium Hydroxide Solution

To find the molar concentration of a solution containing 4.0g of sodium hydroxide (NaOH) in 2L of solution, we can use the formula for molar concentration:

Molar concentration (M) = moles of solute / volume of solution in liters

First, we need to calculate the moles of sodium hydroxide, and then we can use the formula to find the molar concentration.

Calculating Moles of Sodium Hydroxide

The molar mass of sodium hydroxide (NaOH) can be calculated by adding the atomic masses of sodium (Na) and oxygen (O) and hydrogen (H) in the compound. From source the molar mass of NaOH is approximately 40 g/mol.

Using the given mass of sodium hydroxide (4.0g), we can calculate the moles using the formula:

Moles = mass / molar mass

Substituting the given values: Moles = 4.0g / 40 g/mol = 0.1 mol

Calculating Molar Concentration

Now that we have the moles of sodium hydroxide, we can use the formula for molar concentration:

Molar concentration (M) = moles of solute / volume of solution in liters

Substituting the given values: Molar concentration = 0.1 mol / 2L = 0.05 M

So, the molar concentration of the solution containing 4.0g of sodium hydroxide in 2L of solution is 0.05 M.