Question

На 200г муравьиной кислоты подействовали 50 г оксида натрия и 50 г гидроксида натрия . Вычислите какая масса соли образуется в каждом случае . Помогите пожалуйста! Срочно!

Answer 1

2HCOOH+ Na2O--> 2HCOONa+ H2O
1) v(HCOOH)= m /М= 200 г/ 46 г/моль=4,35 моль
2) v(Na2O)=  m /М=  50 г/ 62 г/моль=0,81 моль- в недостатке.расчёты по нему
4) v(HCOONa)= 2v( Na2O)= 0,81*2= 1,62 моль
5) m(HCOONa)= v*M= 1,62*68=110,16 г 

 HCOOH+ NaOН--> HCOONa+ H2O
1)  1) v(HCOOH)= m /М= 200 г/ 46 г/моль=4,35 моль

2) v(NaoH)= m \М= 50 г/ 40 г/моль= 1,25 моль- в недостатке.
3) v(HCOONa)= v( NaOH) =1,25 моль
4) m(HCOONa)= v*M= 1,25*68=85  г 
 

Answer 2

Calculation of Salt Formation

To calculate the mass of salt formed in each case, we need to determine the balanced chemical equation for the reaction between formic acid (HCOOH), sodium oxide (Na2O), and sodium hydroxide (NaOH).

The balanced chemical equation for the reaction can be written as follows:

2 HCOOH + Na2O + 2 NaOH -> 2 NaHCOO + H2O

According to the equation, 2 moles of formic acid react with 1 mole of sodium oxide and 2 moles of sodium hydroxide to produce 2 moles of sodium formate and 1 mole of water.

Now, let's calculate the mass of salt formed in each case.

Given: Mass of formic acid (HCOOH) = 200 g Mass of sodium oxide (Na2O) = 50 g Mass of sodium hydroxide (NaOH) = 50 g

To calculate the mass of salt formed, we need to convert the given masses into moles using the molar masses of the substances involved.

The molar mass of formic acid (HCOOH) is 46.03 g/mol. The molar mass of sodium oxide (Na2O) is 61.98 g/mol. The molar mass of sodium hydroxide (NaOH) is 39.99 g/mol.

Now, let's calculate the number of moles of each substance:

Number of moles of formic acid (HCOOH) = Mass of formic acid / Molar mass of formic acid Number of moles of sodium oxide (Na2O) = Mass of sodium oxide / Molar mass of sodium oxide Number of moles of sodium hydroxide (NaOH) = Mass of sodium hydroxide / Molar mass of sodium hydroxide

Substituting the given values:

Number of moles of formic acid (HCOOH) = 200 g / 46.03 g/mol Number of moles of sodium oxide (Na2O) = 50 g / 61.98 g/mol Number of moles of sodium hydroxide (NaOH) = 50 g / 39.99 g/mol

Now, let's calculate the number of moles of salt formed:

According to the balanced chemical equation, 2 moles of formic acid react to form 2 moles of sodium formate.

Number of moles of sodium formate = Number of moles of formic acid (HCOOH)

Now, let's calculate the mass of salt formed:

Mass of sodium formate = Number of moles of sodium formate * Molar mass of sodium formate

The molar mass of sodium formate (NaHCOO) is 68.01 g/mol.

Substituting the values:

Mass of sodium formate = Number of moles of sodium formate * Molar mass of sodium formate

Now, let's calculate the mass of salt formed in each case.

Case 1: Mass of formic acid (HCOOH) = 200 g Number of moles of formic acid (HCOOH) = 200 g / 46.03 g/mol Number of moles of sodium formate = Number of moles of formic acid (HCOOH) Mass of sodium formate = Number of moles of sodium formate * Molar mass of sodium formate

Case 2: Mass of sodium oxide (Na2O) = 50 g Number of moles of sodium oxide (Na2O) = 50 g / 61.98 g/mol Number of moles of sodium formate = Number of moles of formic acid (HCOOH) Mass of sodium formate = Number of moles of sodium formate * Molar mass of sodium formate

Case 3: Mass of sodium hydroxide (NaOH) = 50 g Number of moles of sodium hydroxide (NaOH) = 50 g / 39.99 g/mol Number of moles of sodium formate = Number of moles of formic acid (HCOOH) Mass of sodium formate = Number of moles of sodium formate * Molar mass of sodium formate

Let's calculate the mass of salt formed in each case.