Question

ХИМИЯ ПОМОГИТЕ ПОЖАЛУЙСТА 8 КЛАСС Рассчитай массы молекул в а.е.м. У следующих веществ: 1. Сахароза C12H22O11 2. Халькопирит CuFeS2 3. Малахит Cu2CO3(OH)2 4. Азурит Cu(CO3)2(OH)2 5. Уксусная кислота CH3COOH 6. Тринитротолуол CH3C6H2(NO2)3

Answer 1

1) считаем массу
12*12(C)+1*22(H)+16*11(O)=342 аем
2) считаем массу
63.5(Cu)+56(Fe)+32*2(S)=183.5 аем
3)считаем массу
63.5*2(Cu)+12(C)+16*5(O)+1*2(H)=221 аем
4)считаем массу
63.5(Сu)+12*2(C)+16*8(O)+1*2(H)=217.5 аем
5)считаем массу
12*2(C)+1*4(Н)+16*2(О)=60 аем
6)считаем массу
12*7(С)+1*5(H)+14*3(N)+16*6(O)=227 аем

Answer 2

Calculation of Molecular Mass in Atomic Mass Units (a.m.u)

To calculate the molecular mass of a compound in atomic mass units (a.m.u), we need to determine the atomic masses of the elements present in the compound and then sum them up according to the molecular formula.

Let's calculate the molecular masses of the given substances:

1. Sucrose (C12H22O11): - Carbon (C) atomic mass = 12.01 a.m.u - Hydrogen (H) atomic mass = 1.008 a.m.u - Oxygen (O) atomic mass = 16.00 a.m.u

Molecular mass of sucrose = (12 * 12.01) + (22 * 1.008) + (11 * 16.00) a.m.u

2. Chalcopyrite (CuFeS2): - Copper (Cu) atomic mass = 63.55 a.m.u - Iron (Fe) atomic mass = 55.85 a.m.u - Sulfur (S) atomic mass = 32.07 a.m.u

Molecular mass of chalcopyrite = (1 * 63.55) + (1 * 55.85) + (2 * 32.07) a.m.u

3. Malachite (Cu2CO3(OH)2): - Copper (Cu) atomic mass = 63.55 a.m.u - Carbon (C) atomic mass = 12.01 a.m.u - Oxygen (O) atomic mass = 16.00 a.m.u - Hydrogen (H) atomic mass = 1.008 a.m.u

Molecular mass of malachite = (2 * 63.55) + (1 * 12.01) + (3 * 16.00) + (2 * 1.008) a.m.u

4. Azurite (Cu(CO3)2(OH)2): - Copper (Cu) atomic mass = 63.55 a.m.u - Carbon (C) atomic mass = 12.01 a.m.u - Oxygen (O) atomic mass = 16.00 a.m.u - Hydrogen (H) atomic mass = 1.008 a.m.u

Molecular mass of azurite = (1 * 63.55) + (2 * 12.01) + (6 * 16.00) + (2 * 1.008) a.m.u

5. Acetic acid (CH3COOH): - Carbon (C) atomic mass = 12.01 a.m.u - Hydrogen (H) atomic mass = 1.008 a.m.u - Oxygen (O) atomic mass = 16.00 a.m.u

Molecular mass of acetic acid = (2 * 12.01) + (4 * 1.008) + (2 * 16.00) a.m.u

6. Trinitrotoluene (CH3C6H2(NO2)3): - Carbon (C) atomic mass = 12.01 a.m.u - Hydrogen (H) atomic mass = 1.008 a.m.u - Nitrogen (N) atomic mass = 14.01 a.m.u - Oxygen (O) atomic mass = 16.00 a.m.u

Molecular mass of trinitrotoluene = (3 * 12.01) + (6 * 1.008) + (2 * 14.01) + (9 * 16.00) a.m.u

Now, let's calculate the molecular masses of the given substances:

1. Sucrose (C12H22O11): Molecular mass of sucrose = (12 * 12.01) + (22 * 1.008) + (11 * 16.00) a.m.u = 342.30 a.m.u [[1]]

2. Chalcopyrite (CuFeS2): Molecular mass of chalcopyrite = (1 * 63.55) + (1 * 55.85) + (2 * 32.07) a.m.u = 183.53 a.m.u [[2]]

3. Malachite (Cu2CO3(OH)2): Molecular mass of malachite = (2 * 63.55) + (1 * 12.01) + (3 * 16.00) + (2 * 1.008) a.m.u = 221.12 a.m.u [[3]]

4. Azurite (Cu(CO3)2(OH)2): Molecular mass of azurite = (1 * 63.55) + (2 * 12.01) + (6 * 16.00) + (2 * 1.008) a.m.u = 376.89 a.m.u [[4]]

5. Acetic acid (CH3COOH): Molecular mass of acetic acid = (2 * 12.01) + (4 * 1.008) + (2 * 16.00) a.m.u = 60.05 a.m.u [[5]]

6. Trinitrotoluene (CH3C6H2(NO2)3): Molecular mass of trinitrotoluene = (3 * 12.01) + (6 * 1.008) + (2 * 14.01) + (9 * 16.00) a.m.u = 227.09 a.m.u [[6]]

Please note that the given molecular masses are approximate and may vary slightly depending on the atomic masses used.

I hope this helps! Let me know if you have any further questions.