
Помогите ! Прошу! Запишите схемы оболочек атомов химических элементов и их электронные формулы с
порядковым номером 13

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13+) ) )
2 8 3
Элемент с порядковым номером 13 всего один, Al



Atomic Shell Diagrams and Electron Configurations for Element with Atomic Number 13
The chemical element with atomic number 13 is aluminum (Al). Here are the atomic shell diagram and electron configuration for aluminum:
Atomic Shell Diagram:
The atomic shell diagram represents the arrangement of electrons in the energy levels or shells around the nucleus of an atom. Each shell is represented by a circle, and the electrons are depicted as dots or lines within the circles. The first shell is closest to the nucleus, followed by the second shell, and so on.
For aluminum (Al), the atomic shell diagram is as follows:
``` 1s^2 2s^2 2p^6 3s^2 3p^1 ```
In the atomic shell diagram, the first shell (K shell) contains 2 electrons, the second shell (L shell) contains 8 electrons, and the third shell (M shell) contains 3 electrons. The electrons are distributed in the shells according to the Aufbau principle, which states that electrons fill the lowest energy levels first before moving to higher energy levels.
Electron Configuration:
The electron configuration of an atom describes how the electrons are distributed among the energy levels or orbitals. It is represented by a series of numbers and letters that indicate the number of electrons in each shell and subshell.
For aluminum (Al), the electron configuration is as follows:
``` 1s^2 2s^2 2p^6 3s^2 3p^1 ```
In the electron configuration, the numbers represent the principal quantum numbers (n) of the shells, and the letters (s, p, d, f) represent the subshells. The superscript numbers indicate the number of electrons in each subshell.
In the case of aluminum, the electron configuration shows that it has 13 electrons. The first shell (n=1) contains 2 electrons, the second shell (n=2) contains 8 electrons, and the third shell (n=3) contains 3 electrons.
I hope this helps! Let me know if you have any further questions.


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