Question

При взаимодействии соляной кислоты с оксидом алюминия образуется соль массой 217г. Рассчитайте массу кислоты,которая потребуется для данной реакции

Answer 1

 x гр                                            217 гр
3НСl         +       Al(OH)3     =    AlCl3          +    3H2O
3*(1+35,5)                                 27+(35,5*3)   
=109,5 гр                                  =133,5 гр

х=m(HCl)=(109,5*217)/133,5= приблизительно 177,99 гр

Answer 2

Calculation of the Mass of Hydrochloric Acid Required

To calculate the mass of hydrochloric acid required for the reaction with aluminum oxide, we need to use the balanced chemical equation for the reaction. However, the balanced equation is not provided in the question. Therefore, I will assume a balanced equation based on the given information.

Assuming the balanced equation for the reaction between hydrochloric acid (HCl) and aluminum oxide (Al2O3) is:

2 HCl + Al2O3 → AlCl3 + H2O

According to the given information, the mass of the resulting salt (AlCl3) is 217 grams. However, we need to find the mass of hydrochloric acid required for this reaction.

To calculate the mass of hydrochloric acid, we can use the stoichiometry of the balanced equation. From the balanced equation, we can see that the molar ratio between HCl and AlCl3 is 2:1. This means that for every 2 moles of HCl, we get 1 mole of AlCl3.

To calculate the mass of HCl, we need to know the molar mass of AlCl3. The molar mass of AlCl3 is the sum of the atomic masses of aluminum (Al) and three chlorine (Cl) atoms.

The atomic mass of Al is approximately 26.98 g/mol, and the atomic mass of Cl is approximately 35.45 g/mol. Therefore, the molar mass of AlCl3 is:

Molar mass of AlCl3 = (26.98 g/mol) + 3 * (35.45 g/mol) = 133.33 g/mol

Now, we can calculate the mass of HCl using the following steps:

Step 1: Calculate the number of moles of AlCl3 using the given mass of AlCl3 and its molar mass.

Number of moles of AlCl3 = Mass of AlCl3 / Molar mass of AlCl3

Step 2: Calculate the number of moles of HCl using the molar ratio from the balanced equation.

Number of moles of HCl = 2 * Number of moles of AlCl3

Step 3: Calculate the mass of HCl using the number of moles of HCl and its molar mass.

Mass of HCl = Number of moles of HCl * Molar mass of HCl

Since we don't have the molar mass of HCl, I will assume it to be approximately 36.46 g/mol, which is the molar mass of hydrochloric acid.

Now, let's calculate the mass of hydrochloric acid required for the given reaction:

Step 1: Number of moles of AlCl3 = 217 g / 133.33 g/mol = 1.627 moles

Step 2: Number of moles of HCl = 2 * 1.627 moles = 3.254 moles

Step 3: Mass of HCl = 3.254 moles * 36.46 g/mol = 118.7 g

Therefore, the mass of hydrochloric acid required for the given reaction is approximately 118.7 grams.

Please note that the molar mass of hydrochloric acid may vary slightly depending on the concentration of the solution used.