Question

На нейтрализацию 25,5 грамм предельной одноосновной кислоты потребовался раствор,содержащий 10 грамм гидроксида натрия.Определите формулу кислоты.

Answer 1

CnH2n+1-COOH+NaOH=CnH2n+1-COONa + H2O;n(NaOH)=10:40=0,25моль;

n(CnH2n+1-COOH)=0,25моль

M(CnH2n+1-COOH)=25,5:0,25=102г/моль

                                              14n+46=102

                                                     n=4

 

Ответ:C4H9-COOH-пентановая кислота.

Answer 2

Calculating the Formula of the Acid

To determine the formula of the acid, we can use the information provided about the neutralization of 25.5 grams of a monobasic acid with a solution containing 10 grams of sodium hydroxide.

The neutralization reaction between an acid and a base can be represented by the following equation: acid + base → salt + water

The molar ratio between the acid and the base can be used to calculate the formula of the acid.

Calculation Steps

1. Calculate the number of moles of sodium hydroxide (NaOH) using its mass. 2. Use the molar ratio between the acid and sodium hydroxide to find the number of moles of the acid. 3. Calculate the molar mass of the acid. 4. Determine the empirical formula of the acid.

Calculation Results

1. Number of moles of NaOH: - Mass of NaOH = 10 grams - Molar mass of NaOH = 40 g/mol - Number of moles = Mass / Molar mass = 10 g / 40 g/mol = 0.25 moles

2. Number of moles of the acid: - From the neutralization reaction, the molar ratio between the acid and NaOH is 1:1. - Therefore, the number of moles of the acid is also 0.25 moles.

3. Molar mass of the acid: - Molar mass of the acid = Mass of acid / Number of moles - Molar mass = 25.5 g / 0.25 mol = 102 g/mol

4. Empirical formula of the acid: - The molar mass of the acid is approximately 102 g/mol.

Conclusion

Based on the given information, the empirical formula of the acid is not explicitly provided. However, using the calculated molar mass of approximately 102 g/mol, further analysis or additional information would be needed to determine the specific formula of the acid.